Question

1. $x^{5}+4x^{3}=0$ gck

$x^{3}(\quad)$

Explanation:

Step1: Factor out GCF $x^3$

$x^3(x^2 + 4) = 0$

Step2: Solve for $x$ from factors

Set $x^3=0$ and $x^2+4=0$

• From $x^3=0$: $x=0$ (multiplicity 3)
• From $x^2+4=0$: $x^2=-4$, so $x=\pm 2i$

Answer:

The factored form is $x^3(x^2 + 4) = 0$, and the solutions are $x=0$, $x=2i$, $x=-2i$