Question

4 > \frac{y}{3} + 6

Explanation:

Step1: Subtract 6 from both sides

$4 - 6 > \frac{y}{3} + 6 - 6$
$-2 > \frac{y}{3}$

Step2: Multiply both sides by 3

$-2 \times 3 > \frac{y}{3} \times 3$
$-6 > y$

Answer:

$y < -6$