Question

1. \sqrt{x - 7} + 5 = 2

Explanation:

Step1: Isolate the square root term

Subtract 5 from both sides.
$\sqrt{x-7} = 2 - 5$
$\sqrt{x-7} = -3$

Step2: Analyze the square root property

The square root of a real number is always non-negative (greater than or equal to 0).
$\sqrt{x-7} \geq 0$ for all real $x$ where $x-7 \geq 0$

Answer:

No real solution exists, since a square root cannot equal a negative number.