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Question
- $-sqrt{20} + sqrt{48} - 3sqrt{125}$
Step1: Simplify each radical term
$-\sqrt{20} = -\sqrt{4\times5} = -2\sqrt{5}$
$\sqrt{48} = \sqrt{16\times3} = 4\sqrt{3}$
$-3\sqrt{125} = -3\sqrt{25\times5} = -3\times5\sqrt{5} = -15\sqrt{5}$
Step2: Combine like radical terms
Combine the terms with $\sqrt{5}$:
$-2\sqrt{5} -15\sqrt{5} + 4\sqrt{3} = (-2-15)\sqrt{5} + 4\sqrt{3}$
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$-17\sqrt{5} + 4\sqrt{3}$