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9) $mangle2 = 6x + 3$ 10) $mangle2=x + 49$

Question

  1. $mangle2 = 6x + 3$
  2. $mangle2=x + 49$

Explanation:

Response
  1. For problem 9:
  • Explanation:
  • Step1: Recall the property of an isosceles - right triangle
  • In the first right - triangle, since the two legs are congruent, the non - right angles are equal. The sum of the interior angles of a triangle is \(180^{\circ}\), and in a right - triangle with two equal non - right angles, each non - right angle is \(45^{\circ}\). So we set up the equation \(6x + 3=45\).
  • Step2: Solve the equation for \(x\)
  • Subtract 3 from both sides of the equation \(6x+3 = 45\): \(6x=45 - 3\), so \(6x = 42\).
  • Then divide both sides by 6: \(x=\frac{42}{6}=7\).
  • Answer: A. 7
  1. For problem 10:
  • Explanation:
  • Step1: Recall the property of an isosceles triangle
  • In the second isosceles triangle, the two base angles are equal. The sum of the interior angles of a triangle is \(180^{\circ}\). Let the base angles be equal. One base angle is \(42^{\circ}\), and the other is \(m\angle2=x + 49\). So \(x+49 = 42\).
  • Step2: Solve the equation for \(x\)
  • Subtract 49 from both sides of the equation \(x + 49=42\): \(x=42-49=-7\).
  • Answer: D. - 7

Answer:

  1. For problem 9:
  • Explanation:
  • Step1: Recall the property of an isosceles - right triangle
  • In the first right - triangle, since the two legs are congruent, the non - right angles are equal. The sum of the interior angles of a triangle is \(180^{\circ}\), and in a right - triangle with two equal non - right angles, each non - right angle is \(45^{\circ}\). So we set up the equation \(6x + 3=45\).
  • Step2: Solve the equation for \(x\)
  • Subtract 3 from both sides of the equation \(6x+3 = 45\): \(6x=45 - 3\), so \(6x = 42\).
  • Then divide both sides by 6: \(x=\frac{42}{6}=7\).
  • Answer: A. 7
  1. For problem 10:
  • Explanation:
  • Step1: Recall the property of an isosceles triangle
  • In the second isosceles triangle, the two base angles are equal. The sum of the interior angles of a triangle is \(180^{\circ}\). Let the base angles be equal. One base angle is \(42^{\circ}\), and the other is \(m\angle2=x + 49\). So \(x+49 = 42\).
  • Step2: Solve the equation for \(x\)
  • Subtract 49 from both sides of the equation \(x + 49=42\): \(x=42-49=-7\).
  • Answer: D. - 7