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add. $(-5y^{2}+y - 8)+(4y^{2}+7y + 5)$

Question

add.
$(-5y^{2}+y - 8)+(4y^{2}+7y + 5)$

Explanation:

Step1: Remove parentheses

$(-5y^{2}+y - 8)+(4y^{2}+7y + 5)=-5y^{2}+y - 8+4y^{2}+7y + 5$

Step2: Combine like terms

For $y^{2}$ terms: $-5y^{2}+4y^{2}=(-5 + 4)y^{2}=-y^{2}$
For $y$ terms: $y+7y=(1 + 7)y = 8y$
For constant terms: $-8 + 5=-3$
So the result is $-y^{2}+8y - 3$

Answer:

$-y^{2}+8y - 3$