Question

d) (2x)²y⁻⁴

Explanation:

Step1: Expand the squared term

$(2x)^2 = 2^2 \cdot x^2 = 4x^2$

Step2: Rewrite negative exponent as positive

$y^{-4} = \frac{1}{y^4}$

Step3: Combine the terms

Multiply the results from Step1 and Step2

Answer:

$\frac{4x^2}{y^4}$