Question

divide.
\\(\

$$\begin{array}{r}9enclose{longdiv}{28.89}\\\\end{array}$$

\\)

Explanation:

Step1: Divide 28 by 9

9 goes into 28 3 times (since \(9\times3 = 27\)). Subtract \(27\) from \(28\), we get \(28 - 27=1\). Bring down the next digit (which is 8, making it 18).

Step2: Divide 18 by 9

9 goes into 18 exactly 2 times. Subtract \(18\) from \(18\), we get \(0\). Now, bring down the last digit (9, making it 9).

Step3: Divide 9 by 9

9 goes into 9 exactly 1 time. Subtract \(9\) from \(9\), we get \(0\).

Step4: Combine the results

Putting it all together, we have \(3.21\) (the 3 from the first division, 2 from the second, and 1 from the third, with the decimal in the correct place).

Mathematically, we can also do it as \(\frac{28.89}{9}\). We know that \(28.89\div9=(27 + 1.89)\div9=27\div9+1.89\div9 = 3+0.21 = 3.21\).

Answer:

\(3.21\)