Question

e $\frac{3}{8}+\frac{9}{16}$ f $\frac{7}{10}-\frac{1}{5}$ g $\frac{1}{3}+\frac{7}{8}$ h $\frac{3}{4}-\frac{1}{10}$ i $\frac{1}{2}+\frac{2}{7}$ j $\frac{4}{5}-\frac{1}{6}$ k $\frac{9}{16}+\frac{15}{16}$ l $\frac{7}{10}-\frac{8}{15}$

Explanation:

Step1: Find common denominator

For E, common - denominator of 8 and 16 is 16.

Step2: Rewrite fractions

$\frac{3}{8}=\frac{3\times2}{8\times2}=\frac{6}{16}$, then $\frac{6}{16}+\frac{9}{16}$.

Step3: Add numerators

$\frac{6 + 9}{16}=\frac{15}{16}$.
(Repeat similar steps for F - L. For subtraction, subtract numerators after rewriting with common denominator; for division, multiply by the reciprocal of the divisor)

Answer:

E. $\frac{3}{8}+\frac{9}{16}=\frac{6 + 9}{16}=\frac{15}{16}$; F. $\frac{7}{10}-\frac{1}{5}=\frac{7 - 2}{10}=\frac{5}{10}=\frac{1}{2}$; G. $\frac{1}{3}+\frac{7}{8}=\frac{8+21}{24}=\frac{29}{24}=1\frac{5}{24}$; H. $\frac{3}{4}-\frac{1}{10}=\frac{15 - 2}{20}=\frac{13}{20}$; I. $\frac{1}{2}\div\frac{2}{7}=\frac{1}{2}\times\frac{7}{2}=\frac{7}{4}=1\frac{3}{4}$; J. $\frac{4}{5}-\frac{1}{6}=\frac{24 - 5}{30}=\frac{19}{30}$; K. $\frac{9}{16}+\frac{15}{16}=\frac{9 + 15}{16}=\frac{24}{16}=\frac{3}{2}=1\frac{1}{2}$; L. $\frac{7}{10}-\frac{8}{15}=\frac{21 - 16}{30}=\frac{5}{30}=\frac{1}{6}$