Question

(\frac{13}{9}) (\bigcirc) (\frac{5}{9}) (\frac{8}{8}) (\bigcirc) (1) (\frac{6}{6}) (\bigcirc) (2) (\frac{4}{7}) (\bigcirc) (\frac{9}{7})

Explanation:

Step1: Compare \(\frac{13}{9}\) and \(\frac{5}{9}\)

For fractions with the same denominator, the fraction with the larger numerator is larger. Since \(13>5\), we have \(\frac{13}{9}>\frac{5}{9}\).

Step2: Compare \(\frac{8}{8}\) and \(1\)

Simplify \(\frac{8}{8}\), which equals \(1\), so \(\frac{8}{8} = 1\).

Step3: Compare \(\frac{6}{6}\) and \(2\)

Simplify \(\frac{6}{6}=1\). Since \(1 < 2\), we have \(\frac{6}{6}<2\).

Step4: Compare \(\frac{4}{7}\) and \(\frac{9}{7}\)

For fractions with the same denominator, the fraction with the larger numerator is larger. Since \(4 < 9\), we have \(\frac{4}{7}<\frac{9}{7}\).
(Note: The first comparison \(\frac{9}{11}\) and \(1\) is partially visible, but assuming we follow the pattern, \(1=\frac{11}{11}\), and since \(9 < 11\), \(\frac{9}{11}<1\))

Answer:

• \(\frac{9}{11}\) \(\boldsymbol{<}\) \(1\)
• \(\frac{13}{9}\) \(\boldsymbol{>}\) \(\frac{5}{9}\)
• \(\frac{8}{8}\) \(\boldsymbol{=}\) \(1\)
• \(\frac{6}{6}\) \(\boldsymbol{<}\) \(2\)
• \(\frac{4}{7}\) \(\boldsymbol{<}\) \(\frac{9}{7}\)