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Question
$-\frac{5^{2}}{4}+3(5)+7 =$
Step1: Calculate the exponent
First, we calculate \(5^2\), which is \(5\times5 = 25\). So the expression becomes \(-\frac{25}{4}+3(5)+7\).
Step2: Calculate the multiplication
Next, we calculate \(3(5)=15\). Now the expression is \(-\frac{25}{4}+15 + 7\).
Step3: Add the integers
Then, we add \(15\) and \(7\), which gives \(15 + 7=22\). So the expression is now \(-\frac{25}{4}+22\).
Step4: Convert to common denominator
To add these two terms, we convert \(22\) to a fraction with denominator \(4\). \(22=\frac{88}{4}\). So the expression becomes \(-\frac{25}{4}+\frac{88}{4}\).
Step5: Add the fractions
Finally, we add the two fractions: \(\frac{- 25+88}{4}=\frac{63}{4}=15.75\).
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\(\frac{63}{4}\) (or \(15.75\))