Question

if $p(x)=x^2 + 3x - 6$ and $q(x)=x - 4$, then what $p(x)-q(x)$?
$x^2 + \square x + \square$

Explanation:

Step1: Substitute given functions

$p(x)-q(x) = (x^2+3x-6)-(x-4)$

Step2: Distribute the negative sign

$p(x)-q(x) = x^2+3x-6-x+4$

Step3: Combine like terms

$p(x)-q(x) = x^2+(3x-x)+(-6+4)$
$p(x)-q(x) = x^2+2x-2$

Answer:

$x^2+2x-2$
(The blanks fill in as: 1, 2, -2 respectively)