Question

p
?
5 in
q 2 in r

Explanation:

Step1: Identify the theorem

Use Pythagorean theorem $a^{2}+b^{2}=c^{2}$, where $a = 2$, $b = 5$, and $c$ is the hypotenuse $PQ$.

Step2: Substitute values

$c^{2}=2^{2}+5^{2}=4 + 25=29$.

Step3: Solve for $c$

$c=\sqrt{29}\text{ in}$.

Answer:

$\sqrt{29}\text{ in}$