Question

simplify.
$\frac{w^{2}-64}{w+8}$

Explanation:

Step1: Factor numerator (difference of squares)

$w^2 - 64 = (w+8)(w-8)$

Step2: Cancel common factor

$\frac{(w+8)(w-8)}{w+8} = w-8$ (where $w
eq -8$)

Answer:

$w - 8$ (with the restriction $w
eq -8$)