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(x + 4)^2 = 13

Question

(x + 4)^2 = 13

Explanation:

Step1: Take square roots of both sides

$\sqrt{(x+4)^2} = \pm\sqrt{13}$

Step2: Simplify left-hand side

$x+4 = \pm\sqrt{13}$

Step3: Isolate x

$x = -4 \pm\sqrt{13}$

Answer:

$x = -4 + \sqrt{13}$ or $x = -4 - \sqrt{13}$