Question

mia and aubrey started kayaking the crow creek river at the same time. mia started at the top of the river and traveled downstream at a speed of 6 miles per hour. aubrey started 4 miles farther down the river and traveled downstream at a speed of 3 miles per hour. if they each kept a constant speed, which equation can you use to find h, the number of hours it took for mia to pass aubrey? $6h = 3h + 4$ $6h = 4h + 3$ how long did it take for mia to pass aubrey? simplify any fractions. hours

Explanation:

Part 1: Finding the Equation

Step1: Determine Mia's Distance

Mia's speed is 6 mph, time is \( h \) hours. Distance = speed × time, so Mia's distance is \( 6h \).

Step2: Determine Aubrey's Distance

Aubrey's speed is 3 mph, time is \( h \) hours, and she started 4 miles ahead. So her distance is \( 3h + 4 \).

Step3: Set Distances Equal

When Mia passes Aubrey, their distances are equal. So \( 6h = 3h + 4 \).

Step1: Subtract \( 3h \) from Both Sides

\( 6h - 3h = 3h + 4 - 3h \) simplifies to \( 3h = 4 \).

Step2: Divide by 3

\( h = \frac{4}{3} \).

Answer:

\( 6h = 3h + 4 \)

Part 2: Solving for \( h \)