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Question
more properties of lines common core geometry homework
- a parallelogram is a four - sided figure that has two pairs of parallel, opposite sides. parallelogram abcd is shown below. if another line was drawn parallel to $overline{cd}$ passing through a, explain why it must fall on $overline{ab}$.
- in the following diagram which is not drawn to scale, why cant both $overline{ab}$ and $overline{ac}$ be perpendicular to $overline{bc}$?
- in exercise #2(c) from the class work we saw that a segment connecting two points on opposite sides of a given line must intersect that line. is it always true that a line connecting two points on the same side of given line will be parallel to that given line?
Step1: Recall parallelogram property
In parallelogram \(ABCD\), \(AB\parallel CD\) by definition of parallelogram.
Step2: Apply parallel - line uniqueness
Through a point \(A\) outside the line \(CD\), there is exactly one line parallel to \(CD\). Since \(AB\) is already parallel to \(CD\) and we are drawing a line parallel to \(CD\) through \(A\), this new line must be the same as \(AB\).
Step1: Recall perpendicular - line property
In a plane, through a given point on a line, there is exactly one line perpendicular to the given line.
Step2: Analyze points \(B\) and \(C\)
Points \(B\) and \(C\) are on line \(BC\). If we consider the point \(B\) on \(BC\), there is a unique perpendicular line to \(BC\) at \(B\) and if we consider point \(C\) on \(BC\), there is a unique perpendicular line to \(BC\) at \(C\). \(AB\) and \(AC\) cannot both be perpendicular to \(BC\) because if \(AB\perp BC\) at \(B\) and \(AC\perp BC\) at \(C\), it would violate the uniqueness of the perpendicular line through a point on a line.
Step1: Consider counter - example
No, it is not always true. We can consider a triangle. For example, in \(\triangle ABC\), points \(A\) and \(B\) are on the same side of the line containing side \(BC\), but the line \(AB\) is not parallel to the line containing side \(BC\). The lines will intersect if extended.
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Because in a parallelogram \(ABCD\), \(AB\parallel CD\) and through a point outside a line there is exactly one line parallel to the given line.