Question

x y (x,y)1 $\frac{1}{2}$ $(1,\frac{1}{2})$2 $1\frac{1}{2}$ $(2,1\frac{1}{2})$3 $2\frac{1}{2}$ $(3,2\frac{1}{2})$more than y 1 x $\frac{1}{2}$ less than is 2

Explanation:

Step1: Analyze table values

For each $x$: $x=1, y=\frac{1}{2}$; $x=2, y=1\frac{1}{2}=1+\frac{1}{2}$; $x=3, y=2\frac{1}{2}=2+\frac{1}{2}$

Step2: Derive relationship

Rewrite $y$ in terms of $x$: $y = x - \frac{1}{2}$, so $y$ is $\frac{1}{2}$ less than $x$.

Answer:

$y$ is $\frac{1}{2}$ less than $x$