Question

for a moving object, the force acting on the object varies directly with the objects acceleration. when a force of 45 n acts on a certain object, the acceleration of the object is 5 m/s². if the acceleration of the object becomes 4 m/s², what is the force?

Explanation:

Step1: Find the constant of variation

Since force $F$ varies directly with acceleration $a$, we have $F = ka$. When $F = 45$ N and $a=5$ m/s², we can find $k$ by substituting these values into the equation: $45=k\times5$. Solving for $k$, we get $k=\frac{45}{5} = 9$.

Step2: Calculate the new force

Now that we know $k = 9$, and the new acceleration $a = 4$ m/s². We use the equation $F=ka$ again. Substitute $k = 9$ and $a = 4$ into it, so $F=9\times4=36$ N.

Answer:

36