Question

1. mr. harper walks 350 meters from his classroom to raider burrito to get breakfast. he walks back to the teachers lounge to eat his breakfast, which is 825 meters from raider burrito. it took mr. harper 1525 seconds to walk the entire trip. what is his total displacement and average velocity of his trip? (v=d/t) (displacement= final position- initial position)
2. a train travels 120 km in 2 hours and 30 minutes. what is its average speed in meters per second? (convert time to seconds and kilometers to meters)

Explanation:

8)

Step1: Define displacement formula

Displacement = final position - initial position

Step2: Analyze Mr. Harper's trip

He starts from classroom, goes to Raider Burrito and then to teachers lounge. But we assume he ends up at a position relative to his starting - point (classroom) which is the same. So final position - initial position = 0 meters.

Step3: Calculate average velocity

Average velocity \(v=\frac{D}{t}\), where \(D\) is displacement and \(t\) is time. Since \(D = 0\) meters and \(t=1525\) seconds, \(v=\frac{0}{1525}=0\) m/s

9)

Step1: Convert distance to meters

Given distance \(d = 120\) km. Since \(1\) km=\(1000\) m, \(d=120\times1000 = 120000\) m

Step2: Convert time to seconds

Given time \(t = 2\) hours and 30 minutes. 2 hours \(=2\times3600=7200\) seconds, 30 minutes \(=30\times60 = 1800\) seconds. So \(t=7200 + 1800=9000\) seconds

Step3: Calculate average speed

Average speed \(v=\frac{d}{t}\), substituting \(d = 120000\) m and \(t = 9000\) s, we get \(v=\frac{120000}{9000}=\frac{40}{3}\approx13.33\) m/s

Answer:

Total displacement: 0 meters; Average velocity: 0 m/s