Question

multiply.
5v·2

Explanation:

Step1: Recall exponent rule for multiplication

When multiplying variables with exponents, we use the rule \(a^m \cdot a^n = a^{m + n}\), and for coefficients, we multiply them normally. Here, we have \(5v \cdot 2\). Wait, maybe it's \(5v^{-2}\)? Wait, the original is \(5v\cdot2\)? Wait, no, maybe the user meant \(5v \times 2\) or \(5v^{-2}\)? Wait, the problem says "Multiply. \(5v\cdot2\)". So we multiply the coefficient 5 and 2, and the variable part remains as is.

Step2: Multiply the coefficients

The coefficients are 5 and 2. Multiplying them: \(5\times2 = 10\). The variable part is \(v\) (assuming the exponent on \(v\) is 1, so \(v^1\)). So combining them, we get \(10v\). Wait, but if it was \(5v^{-2}\times2\), but the original is \(5v\cdot2\). So let's recheck. The expression is \(5v \cdot 2\), which is \(5\times2\times v=10v\).

Answer:

\(10v\)