Question

name quinn boncek period date algebra 1 cp: modified unit 4 assessment ____/54 = __% 1. graph the line whose x - intercept is 9 and whose y - intercept is 6. 2pts plot (9,0) and (0,6) 2. the equation of a line is given below. make x zero - for y int, make y zero - for x int. x - 2y = - 8 find the x - intercept and y - intercept. then use them to graph the line. 5pts x - intercept: (, ) y - intercept: (, __)

Explanation:

Problem 2 Solution:

Step1: Find x - intercept (set y = 0)

Substitute \( y = 0 \) into the equation \( x - 2y=-8 \).
\( x - 2(0)=-8 \)
\( x=-8 \)
So the x - intercept is the point \((-8,0)\).

Step2: Find y - intercept (set x = 0)

Substitute \( x = 0 \) into the equation \( x - 2y=-8 \).
\( 0 - 2y=-8 \)
Divide both sides by - 2: \( y=\frac{-8}{-2}=4 \)
So the y - intercept is the point \((0,4)\).

Answer:

x - intercept: \((-8,0)\)
y - intercept: \((0,4)\)

Problem 1 Explanation (for graphing):

To graph the line with x - intercept 9 (point \((9,0)\)) and y - intercept 6 (point \((0,6)\)):

1. Locate the point \((9,0)\) on the x - axis (9 units to the right of the origin) and the point \((0,6)\) on the y - axis (6 units up from the origin).
2. Use a straightedge to draw a line connecting these two points. This line represents the equation of the line with x - intercept 9 and y - intercept 6. (Since the problem asks to plot the points and graph, the key is to identify and plot \((9,0)\) and \((0,6)\) and draw the line through them.)