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Question
name sylvester williams date 2/10 block 1a
math 1b homework: writing equations in slope-intercept form
write each standard form equation in slope-intercept form. graph the equation when a graph is provided. (#4, 6, 8 )
- $x + y = -1$
- $2y = -1x - 8$
- $-2x + y = 1$
- $2x - 3y = 9$
- $6x + 2y = 12$
- $3x - 5y = 10$
- $2x - y = 4$
- $6x + 2y = -6$
Step1: Isolate $y$ for #1
$x + y = -1 \implies y = -x - 1$
Step2: Isolate $y$ for #2
$2y = -x - 8 \implies y = \frac{-x - 8}{2} = -\frac{1}{2}x - 4$
Step3: Isolate $y$ for #3
$-2x + y = 1 \implies y = 2x + 1$
Step4: Isolate $y$ for #4
$2x - 3y = 9 \implies -3y = -2x + 9 \implies y = \frac{2}{3}x - 3$
Step5: Isolate $y$ for #5
$6x + 2y = 12 \implies 2y = -6x + 12 \implies y = -3x + 6$
Step6: Isolate $y$ for #6
$3x - 5y = 10 \implies -5y = -3x + 10 \implies y = \frac{3}{5}x - 2$
Step7: Isolate $y$ for #7
$2x - y = 4 \implies -y = -2x + 4 \implies y = 2x - 4$
Step8: Isolate $y$ for #8
$6x + 2y = -6 \implies 2y = -6x - 6 \implies y = -3x - 3$
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- $y = -x - 1$
- $y = -\frac{1}{2}x - 4$
- $y = 2x + 1$
- $y = \frac{2}{3}x - 3$ (Graph: Plot y-intercept $(0, -3)$, then use slope $\frac{2}{3}$ to plot another point (right 3, up 2) and draw the line)
- $y = -3x + 6$
- $y = \frac{3}{5}x - 2$ (Graph: Plot y-intercept $(0, -2)$, then use slope $\frac{3}{5}$ to plot another point (right 5, up 3) and draw the line)
- $y = 2x - 4$
- $y = -3x - 3$ (Graph: Plot y-intercept $(0, -3)$, then use slope $-3$ to plot another point (right 1, down 3) and draw the line)