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nancy drew a scale drawing of a petting zoo. the goat pen, which is 9 m…

Question

nancy drew a scale drawing of a petting zoo. the goat pen, which is 9 meters wide in real life, is 15 centimeters wide in the drawing. what is the scale of the drawing? 5 centimeters : square meters

Explanation:

Step1: Convert real - life width to centimeters

We know that 1 meter = 100 centimeters. So, the real - life width of the goat pen is 9 meters. To convert meters to centimeters, we multiply by 100. So, \(9\times100 = 900\) centimeters.

Step2: Find the scale

The scale of a drawing is the ratio of the length in the drawing to the actual length. The length in the drawing is 15 centimeters and the actual length is 900 centimeters. So, the scale is \(\frac{15}{900}=\frac{1}{60}\). But the problem is presented as 5 centimeters : [ ] meters. Wait, maybe there is a mis - reading. Wait, the original problem: The goat pen is 9 meters wide in real life, 15 centimeters wide in the drawing. Wait, maybe the question is about a different part? Wait, the user's problem has "5 centimeters : [ ] meters". Wait, maybe it's a ratio problem. Let's re - examine.

Wait, maybe the first part is: The goat pen is 9 meters (900 cm) wide in real life, 15 cm in the drawing. Then we can find the scale factor. Let's assume that for 5 cm in the drawing, we want to find the real - life length in meters.

First, find the scale factor. The scale factor \(k=\frac{\text{Real length}}{\text{Drawing length}}=\frac{900\ cm}{15\ cm}=60\).

Now, if the drawing length is 5 cm, then the real - life length \(L = 5\times k\) (in cm). So, \(L = 5\times60=300\ cm\). Convert 300 cm to meters: \(300\div100 = 3\) meters.

Wait, maybe the problem is: The scale is such that 15 cm (drawing) corresponds to 9 m (real). We can set up a proportion. Let \(x\) be the real - life length in meters when the drawing length is 5 cm.

First, convert 9 meters to centimeters: \(9\times100 = 900\) cm.

Set up the proportion: \(\frac{15\ cm}{900\ cm}=\frac{5\ cm}{y\ cm}\), where \(y\) is the real - life length in cm.

Cross - multiply: \(15y=900\times5\)

\(15y = 4500\)

\(y=\frac{4500}{15}=300\) cm.

Convert 300 cm to meters: \(300\div100 = 3\) meters.

Answer:

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