Question

next, find the width w of the rectangle by using the distance formula. let the width be equal to ab.
w = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}
=\sqrt{0 - (-4)^2+(-2)-2^2}
=\sqrt{ +}
= __
distance formula
let (x_1,y_1)=a(-4,2) and (x_2,y_2)=b(0,-2).
subtract.
simplify.

Explanation:

Step1: Calculate the values inside the square - root

First, calculate $[0-(-4)]^2$ and $[(-2) - 2]^2$.
$[0-(-4)]^2=(0 + 4)^2=4^2 = 16$ and $[(-2)-2]^2=(-4)^2 = 16$.

Step2: Add the results and find the square - root

Add the two results: $16+16 = 32$. Then, $w=\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}$.

Answer:

$4\sqrt{2}$