Question

nick is solving the equation $3x^2 = 20 - 7x$ with the quadratic formula. which values could he use for $a$, $b$, and $c$? $\circ$ $a = 3, b = 20, c = -7$ $\circ$ $a = 3, b = -7, c = 20$ $\circ$ $a = 3, b = 7, c = -20$ $\circ$ $a = 3, b = -20, c = 7$

Explanation:

Step1: Rewrite the equation in standard form

The standard form of a quadratic equation is \(ax^{2}+bx + c = 0\). Given the equation \(3x^{2}=20 - 7x\), we need to move all terms to one side. Add \(7x\) to both sides and subtract \(20\) from both sides: \(3x^{2}+7x - 20=0\).

Step2: Identify a, b, c

In the standard form \(ax^{2}+bx + c = 0\), for the equation \(3x^{2}+7x - 20 = 0\), we have \(a = 3\), \(b = 7\), and \(c=- 20\) (since \(c\) is the constant term, and here it is \(-20\)).

Answer:

a = 3, b = 7, c = -20 (the third option)