Question

1. a nitrogen gas sample is measured at 8.25l and 112kpa at a temperature of 370k. if the pressure and temperature are changed to 139kpa and 660k respectively, the volume will change to ______l

Explanation:

Step1: Recall the combined - gas law

The combined - gas law is $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$.

Step2: Identify the given values

$P_1 = 112\ kPa$, $V_1=8.25\ L$, $T_1 = 370\ K$, $P_2 = 139\ kPa$, $T_2=660\ K$.

Step3: Rearrange the formula for $V_2$

$V_2=\frac{P_1V_1T_2}{T_1P_2}$.

Step4: Substitute the values into the formula

$V_2=\frac{112\ kPa\times8.25\ L\times660\ K}{370\ K\times139\ kPa}$.
First, calculate the numerator: $112\times8.25\times660 = 112\times5445=609840$.
Then, calculate the denominator: $370\times139 = 51430$.
$V_2=\frac{609840}{51430}\approx11.9\ L$.

Answer:

$11.9$