Question

$3x(2x+3)-1(2x+3)$
$(3x-1)(2x+3)$

1. $-4x^{2}-5x+9$

now, pick 3 problems to fin

Explanation:

Step1: Factor out -1

$-(4x^2 + 5x - 9)$

Step2: Factor quadratic inside parentheses

Find two numbers that multiply to $4\times(-9)=-36$ and add to 5: 9 and -4.
Rewrite middle term: $4x^2 + 9x - 4x - 9$
Group and factor: $x(4x+9)-1(4x+9)=(4x+9)(x-1)$

Step3: Combine with factored -1

$-(4x+9)(x-1)=( -4x -9)(x-1)$ or $(4x+9)(-x+1)$

Answer:

$-(4x+9)(x-1)$ (or equivalent forms: $(-4x-9)(x-1)$ or $(4x+9)(1-x)$)