Question

nswer the questions below.
(a) the area of a rectangular field is 8712 m².
if the length of the field is 99 m, what is its width?
width of the field: m
(b) the perimeter of a rectangular painting is 328 cm.
if the width of the painting is 72 cm, what is its length?
length of the painting: cm

Explanation:

Part (a)

Step1: Recall area formula for rectangle

The area \( A \) of a rectangle is given by \( A = \text{length} \times \text{width} \), so \( \text{width} = \frac{A}{\text{length}} \).

Step2: Substitute values

Given \( A = 8712 \, \text{m}^2 \) and length \( = 99 \, \text{m} \), then width \( = \frac{8712}{99} \).
Calculate \( \frac{8712}{99} = 88 \).

Step1: Recall perimeter formula for rectangle

The perimeter \( P \) of a rectangle is \( P = 2(\text{length} + \text{width}) \), so \( \text{length} = \frac{P}{2} - \text{width} \).

Step2: Substitute values

Given \( P = 328 \, \text{cm} \) and width \( = 72 \, \text{cm} \), first find \( \frac{P}{2} = \frac{328}{2} = 164 \, \text{cm} \).
Then length \( = 164 - 72 = 92 \, \text{cm} \).

Answer:

88

Part (b)