Question

1 numeric 1 point
given
$f(x)=\

$$\begin{cases}-(x + 1)^2 + 1 & \\text{for } x < 2 \\\\ x - 1 & \\text{for } x \\geq 5\\end{cases}$$

$
find: $f(-1)$
answer

Explanation:

Step1: Select correct function branch

Since $-1 < 2$, use $f(x) = -(x+1)^2 + 1$.

Step2: Substitute $x=-1$ into formula

$$f(-1) = -(-1+1)^2 + 1$$

Step3: Simplify the expression

$$f(-1) = -(0)^2 + 1 = 0 + 1 = 1$$

Answer:

1