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ok, lets see if youve got the right idea: how many joules would it take to raise 10 grams of water 1 degree? 4.186 joules 0.4186 joules 41.86 joules rewatch
Step1: Recall the specific heat capacity of water
The specific heat capacity of water, \( c \), is \( 4.186 \, \text{J/g}^\circ\text{C} \). This means it takes \( 4.186 \) Joules to raise \( 1 \) gram of water by \( 1^\circ\text{C} \).
Step2: Use the formula for heat energy \( Q = mc\Delta T \)
Here, mass \( m = 10 \, \text{g} \), specific heat capacity \( c = 4.186 \, \text{J/g}^\circ\text{C} \), and temperature change \( \Delta T = 1^\circ\text{C} \).
Substitute the values into the formula:
\( Q = 10 \, \text{g} \times 4.186 \, \text{J/g}^\circ\text{C} \times 1^\circ\text{C} \)
Step3: Calculate the heat energy
\( Q = 10 \times 4.186 \times 1 = 41.86 \, \text{J} \)
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41.86 Joules (corresponding to the option "41.86 Joules")