Question

one of the factors of g² - 32g + 256 is

g + 8

g - 8

g - 16

g + 16

Explanation:

Step1: Identify the quadratic form

The expression $g^{2}-32g + 256$ is in the form of $a^{2}-2ab + b^{2}$ where $a = g$ and $2b=32$ (so $b = 16$).

Step2: Apply the perfect - square formula

The perfect - square formula $a^{2}-2ab + b^{2}=(a - b)^{2}$. Substituting $a = g$ and $b = 16$, we get $g^{2}-32g + 256=(g - 16)^{2}$.

Answer:

C. $g - 16$