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Question
in the parallelogram shown, ae = t + 2, ce = 3t - 14, and de = 2t + 8. what is the length of line segment db? 20 units 24 units 48 units 68 units
Step1: Diagonals bisect in parallelogram
AE = CE
Step2: Solve for t
t + 2 = 3t - 14 → 2t = 16 → t = 8
Step3: Find DE length
DE = 2t + 8 = 2(8) + 8 = 24
Step4: DB = 2×DE
DB = 2×24 = 48
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C. 48 units