Question

a park has grass and sand. find the area of the part with grass. (sides meet at right angles.) square meters

Explanation:

Step1: Calculate area of the park (square)

The park is a square with side length \( 5 \, \text{m} \). The area of a square is \( \text{side}^2 \), so the area of the park is \( 5 \times 5 = 25 \, \text{square meters} \).

Step2: Calculate area of the sand (rectangle)

The sand is a rectangle with length \( 3 \, \text{m} \) and width \( 2 \, \text{m} \)? Wait, no, looking at the diagram, the sand has height \( 3 \, \text{m} \) and width \( 2 \, \text{m} \)? Wait, actually, the sand's dimensions: from the diagram, the sand is a rectangle with length \( 3 \, \text{m} \)? Wait, no, the sand's height is \( 3 \, \text{m} \) (since the middle part is 3m) and width \( 2 \, \text{m} \). So area of sand is \( 3 \times 2 = 6 \, \text{square meters} \)? Wait, no, wait the park is 5x5, and the sand is a rectangle. Wait, let's recheck: the park is a square of 5m x 5m. The sand is a rectangle with length \( 3 \, \text{m} \)? Wait, no, the sand's height is \( 3 \, \text{m} \) (from the 1m + 3m + 1m? Wait, 1 + 3 + 1 = 5, so the total height is 5m. The sand is in the middle, with width 2m and height 3m. So area of sand is \( 3 \times 2 = 6 \, \text{square meters} \). Then the grass area is park area minus sand area: \( 25 - 6 = 19 \)? Wait, no, wait maybe I made a mistake. Wait, the park is 5x5=25. The sand: let's see the sand's dimensions. The sand has a width of 2m (as per the diagram: the sand is labeled with 2m) and height of 3m (since the vertical sides: 1m above, 3m middle, 1m below, so total 5m). So sand area is \( 3 \times 2 = 6 \). Then grass area is \( 25 - 6 = 19 \)? Wait, but let's check another way. The grass can be considered as the big square minus the sand rectangle. Alternatively, we can calculate the grass area by adding the areas of the three blue rectangles (top, middle right, bottom). Top: 5m x 1m = 5. Bottom: 5m x 1m = 5. Middle right: 3m x 3m? Wait, no, middle right: the middle part (between the sand and the right) is 3m (horizontal) and the vertical length is 5 - 1 -1 = 3m? Wait, no, the total height is 5m, top and bottom are 1m each, so middle height is 3m. The middle right: width 3m (horizontal) and height 3m? No, the sand is 2m wide (horizontal) and 3m tall (vertical). So the middle right (grass) is (5 - 2)m wide (since sand is 2m wide) and 3m tall? Wait, 5 - 2 = 3m. So middle right grass: 3m x 3m = 9. Top grass: 5m x 1m = 5. Bottom grass: 5m x 1m = 5. Then total grass: 5 + 9 + 5 = 19. Yes, that matches. So either way, park area (25) minus sand area (6) is 19. Wait, but let's confirm the sand area. Sand is 3m (height) x 2m (width) = 6. So 25 - 6 = 19. So the grass area is 19 square meters.

Answer:

19