Question

part 3 of 4
label the center and the radius r.
(h, k) = (6, 2) and r = 5.
the standard form of the equation of a circle is ((x - h)^2 + (y - k)^2 = r^2).
substitute the values for h, k, and r and simplify.
((square)^2 + (square)^2 = square)

Explanation:

Step1: Substitute h=6 into $(x-h)$

$(x - 6)$

Step2: Substitute k=2 into $(y-k)$

$(y - 2)$

Step3: Calculate $r^2$ with r=5

$r^2 = 5^2 = 25$

Answer:

$(x-6)^2 + (y-2)^2 = 25$