Question

part f
if you wanted to move an electron from the positive to the negative terminal of the battery, how much work w would you need to do on the electron?
enter your answer in joules.
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w = j
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Explanation:

Step1: Recall work - potential relationship

The work done $W$ in moving a charge $q$ through a potential difference $\Delta V$ is given by $W = q\Delta V$.

Step2: Identify charge of an electron and potential difference

The charge of an electron $q=- 1.6\times10^{-19}\text{ C}$. Assume the potential difference of the battery is $\Delta V = V$. The work done in moving the electron from the positive to the negative terminal (against the electric - field direction) is $W=|q|\Delta V$. If the potential difference of the battery is $V$, then $W=(1.6\times10^{-19}\text{ C})\times V$. Let's assume the battery has a potential difference $\Delta V = 1.5\text{ V}$ (a common battery voltage). Then $W=(1.6\times10^{-19}\text{ C})\times1.5\text{ V}=2.4\times10^{-19}\text{ J}$.

Answer:

$2.4\times10^{-19}$ (assuming a battery potential difference of $1.5\text{ V}$). If the potential difference of the battery is different, you can substitute the actual value of $\Delta V$ into the formula $W = 1.6\times10^{-19}\Delta V$ to get the correct answer.