Question

for the piecewise linear function, find (a) f(-4), (b) f(-1), (c) f(0), (d) f(2), and (e) f(4).
$f(x)= \

$$\begin{cases} 2x & \\text{if } x \\leq -1 \\\\ x - 1 & \\text{if } x > -1 \\end{cases}$$

$
(a) $f(-4) = -8$
(b) $f(-1) = -2$
(c) $f(0) = \square$

Explanation:

Step1: Determine the applicable piece

Since \(0 > -1\), we use the piece \(f(x)=x - 1\) for \(x = 0\).

Step2: Substitute \(x = 0\) into the function

Substitute \(x = 0\) into \(f(x)=x - 1\), we get \(f(0)=0 - 1\).

Step3: Calculate the result

\(0 - 1=-1\).

Answer:

\(-1\)