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plot the point. then plot the point that is symmetric to it with respec…

Question

plot the point. then plot the point that is symmetric to it with respect to (a) the x - axis; (b) the y - axis; (c) the origin. (-2,1) plot the point (-2,1). (a) plot the point that is symmetric to (-2,1) with respect to the x - axis. (b) plot the point that is symmetric to (-2,1) with respect to the y - axis.

Explanation:

Step1: Recall x - axis symmetry rule

For a point $(x,y)$ symmetric to the x - axis, the new point is $(x, - y)$. Given the point $(-2,1)$, when symmetric to the x - axis, we change the sign of the y - coordinate.
$(-2,-1)$

Step2: Recall y - axis symmetry rule

For a point $(x,y)$ symmetric to the y - axis, the new point is $(-x,y)$. Given the point $(-2,1)$, when symmetric to the y - axis, we change the sign of the x - coordinate.
$(2,1)$

Step3: Recall origin symmetry rule

For a point $(x,y)$ symmetric to the origin, the new point is $(-x,-y)$. Given the point $(-2,1)$, when symmetric to the origin, we change the signs of both x and y coordinates.
$(2,-1)$

Answer:

(a) $(-2,-1)$
(b) $(2,1)$
(c) $(2,-1)$