Question

y = x - 7\
y = -\frac{1}{3}x - 3\
plot two lines by clicking the graph.\
click a line to delete it.

Explanation:

Step1: Identify intercepts for $y=x-7$

To find the y-intercept, set $x=0$:
$y = 0 - 7 = -7$, so the point is $(0, -7)$.
To find the x-intercept, set $y=0$:
$0 = x - 7 \implies x=7$, so the point is $(7, 0)$.

Step2: Identify intercepts for $y=-\frac{1}{3}x-3$

To find the y-intercept, set $x=0$:
$y = -\frac{1}{3}(0) - 3 = -3$, so the point is $(0, -3)$.
To find the x-intercept, set $y=0$:
$0 = -\frac{1}{3}x - 3 \implies \frac{1}{3}x = -3 \implies x = -9$, so the point is $(-9, 0)$.

Step3: Plot and connect points

For $y=x-7$: plot $(0, -7)$ and $(7, 0)$, then draw a line through them.
For $y=-\frac{1}{3}x-3$: plot $(0, -3)$ and $(-9, 0)$, then draw a line through them.

Answer:

• Line 1 ($y=x-7$) passes through $(0, -7)$ and $(7, 0)$.
• Line 2 ($y=-\frac{1}{3}x-3$) passes through $(0, -3)$ and $(-9, 0)$.

(Plot these points and connect them to form the two required lines on the graph.)