Question

the point k(-3, 6) is reflected over the y-axis. what are the coordinates of the resulting point, k?
k\left(\square, \square\
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Explanation:

Step1: Recall reflection over y - axis rule

The rule for reflecting a point \((x,y)\) over the \(y\) - axis is that the \(x\) - coordinate changes its sign and the \(y\) - coordinate remains the same. Mathematically, if we have a point \(P(x,y)\), after reflection over the \(y\) - axis, the new point \(P'\) has coordinates \((-x,y)\).

Step2: Apply the rule to point \(K(-3,6)\)

For the point \(K(-3,6)\), here \(x=-3\) and \(y = 6\). When we reflect over the \(y\) - axis, the new \(x\) - coordinate is \(-(-3)=3\) and the \(y\) - coordinate remains \(6\). So the coordinates of \(K'\) are \((3,6)\).

Answer:

\(K'(3,6)\)