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practice busing formulas in geometryuse the figures for exercises 1-3.1. find the perimeter of triangle a.2. find the area of triangle a.3. triangle a is identical to triangle b.find the height $h$ of triangle b.find the perimeter and area of each shape.4. square with a side 2.4 m in length5. rectangle with length $(x + 3)$ and width 76. although a circle does not have sides, it does have a perimeter.what is the term for the perimeter of a circle?find the circumference and area of each circle.7. use $\frac{22}{7}$ for $pi$.8. use 3.14 for $pi$.9. leave $pi$ as $pi$.10. the area of a square is $\frac{1}{4}$ $\text{in}^2$. find the perimeter.11. the area of a triangle is $152$ $\text{m}^2$, and the height is 16 m. find the base.12. the circumference of a circle is $25pi$ mm. find the radius.use the figure for exercises 13 and 14.lucas has a 39-foot-long rope. he uses all the rope to outline this t-shape in his backyard. all the angles in the figure are right angles.13. find $x$.14. find the area enclosed by the rope.
Step1: Sum all sides of Triangle A
$3 + 4 + 5 = 12$
Step2: Apply triangle area formula for A
$\text{Area} = \frac{1}{2} \times 3 \times 4 = 6$
Step3: Set equal areas for A and B
$\frac{1}{2} \times 5 \times h = 6$
Solve for $h$: $h = \frac{12}{5} = 2.4$
Step4: Square perimeter and area
Perimeter: $4 \times 2.4 = 9.6$
Area: $2.4^2 = 5.76$
Step5: Rectangle perimeter and area
Perimeter: $2[(x+3)+7] = 2x + 20$
Area: $7(x+3) = 7x + 21$
Step6: Identify circle perimeter term
Recall standard geometry terminology
Step7: Circle 7 circumference and area
Radius $r = \frac{14}{2} = 7$
Circumference: $2 \times \frac{22}{7} \times 7 = 44$
Area: $\frac{22}{7} \times 7^2 = 154$
Step8: Circle 8 circumference and area
Circumference: $2 \times 3.14 \times 1.5 = 9.42$
Area: $3.14 \times 1.5^2 = 7.065$
Step9: Circle 9 circumference and area
Circumference: $2\pi(x+1) = 2\pi x + 2\pi$
Area: $\pi(x+1)^2 = \pi(x^2 + 2x + 1)$
Step10: Find square side then perimeter
Side length $s = \sqrt{\frac{1}{4}} = \frac{1}{2}$
Perimeter: $4 \times \frac{1}{2} = 2$
Step11: Solve for triangle base
Rearrange area formula: $b = \frac{2 \times 152}{16} = 19$
Step12: Solve for circle radius
Rearrange circumference formula: $r = \frac{25\pi}{2\pi} = \frac{25}{2} = 12.5$
Step13: Set perimeter equal to rope length
$2(9 + 3 + x) + 2(9 - 3.5 - 3.5) = 39$
Simplify: $2(12 + x) + 2(2) = 39$
$24 + 2x + 4 = 39$
$2x = 11$
$x = 5.5$
Step14: Calculate T-shape area
Area = Area of top rectangle + Area of bottom rectangle
$= 9 \times 3 + (9 - 3.5 - 3.5) \times 5.5$
$= 27 + 2 \times 5.5 = 27 + 11 = 38$
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- $12$ ft
- $6$ ft$^2$
- $2.4$ ft
- Perimeter: $9.6$ m, Area: $5.76$ m$^2$
- Perimeter: $2x + 20$, Area: $7x + 21$
- Circumference
- Circumference: $44$ mi, Area: $154$ mi$^2$
- Circumference: $9.42$ cm, Area: $7.065$ cm$^2$
- Circumference: $2\pi x + 2\pi$, Area: $\pi x^2 + 2\pi x + \pi$
- $2$ in
- $19$ m
- $12.5$ mm
- $5.5$ ft
- $38$ ft$^2$