Question

practice & problem
leveled practice in 8-11, find the area
8.
2 yd
6 yd
$a = b \cdot h$
$= \square \cdot 6$
$= \square$ $yd^{2}$
10.
$10\frac{1}{2}$ in.
10 in.

Explanation:

Step1: Identify base for Q8

Base $b = 2$ yd

Step2: Substitute into area formula (Q8)

$A = 2 \cdot 6$

Step3: Calculate area for Q8

$A = 12$

Step4: Identify base/height for Q10

Base $b = 10\frac{1}{2}$ in, Height $h = 10$ in

Step5: Substitute into area formula (Q10)

$A = 10\frac{1}{2} \cdot 10$

Step6: Convert mixed number (Q10)

$10\frac{1}{2} = \frac{21}{2}$, so $A = \frac{21}{2} \cdot 10$

Step7: Calculate area for Q10

$A = 105$

Answer:

For question 8: $12$ yd²
For question 10: $105$ in²