QUESTION IMAGE
Question
- a. predict whether each combination of angles in the following table will make a star. if a combination will make a star, predict the number of points it will have.
| measure of the interior angle at each point (a) | measure of the exterior angles between adjacent arms (b) | makes a star? (yes/no) | number of points (n) |
|---|---|---|---|
| 25° | 70° | ||
| 20° | 100° | ||
| 15° | 60° |
b. check your predictions by trying to construct each star.
- give 3 different combinations for angle measures a and b that will form a nine - pointed star.
Step1: Recall the formula
For a star - shaped polygon, the relationship between the interior angle at each point ($a$) and the exterior angle between adjacent arms ($b$) and the number of points ($N$) is given by the formula $b = 2a+\frac{360^{\circ}}{N}$ or $N=\frac{360^{\circ}}{b - 2a}$ (when $b>2a$). If $b\leq2a$, a star - shaped polygon cannot be formed.
Step2: Analyze the first row ($a = 33^{\circ},b = 105^{\circ}$)
Calculate $b-2a$: $b - 2a=105 - 2\times33=105 - 66 = 39^{\circ}$. Then $N=\frac{360}{39}=\frac{120}{13}
otin\mathbb{Z}$ (not an integer). So, it does not make a star.
Step3: Analyze the second row ($a = 25^{\circ},b = 70^{\circ}$)
Calculate $b - 2a$: $b-2a=70 - 2\times25=70 - 50 = 20^{\circ}$. Then $N=\frac{360}{20}=18$. So, it makes a star and has 18 points.
Step4: Analyze the third row ($a = 20^{\circ},b = 100^{\circ}$)
Calculate $b - 2a$: $b-2a=100 - 2\times20=100 - 40 = 60^{\circ}$. Then $N=\frac{360}{60}=6$. So, it makes a star and has 6 points.
Step5: Analyze the fourth row ($a = 15^{\circ},b = 60^{\circ}$)
Calculate $b - 2a$: $b-2a=60 - 2\times15=60 - 30 = 30^{\circ}$. Then $N=\frac{360}{30}=12$. So, it makes a star and has 12 points.
Step6: For forming a nine - pointed star ($N = 9$)
From $N=\frac{360}{b - 2a}$, we have $b-2a = 40^{\circ}$.
- Combination 1: Let $a = 10^{\circ}$, then $b=2a + 40^{\circ}=2\times10+40=60^{\circ}$.
- Combination 2: Let $a = 15^{\circ}$, then $b=2\times15 + 40=70^{\circ}$.
- Combination 3: Let $a = 20^{\circ}$, then $b=2\times20+40 = 80^{\circ}$.
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| Measure of the interior angle at each point ($a$) | Measure of the exterior angles between adjacent arms ($b$) | Makes a star? (yes/no) | Number of points ($N$) |
|---|---|---|---|
| $25^{\circ}$ | $70^{\circ}$ | yes | 18 |
| $20^{\circ}$ | $100^{\circ}$ | yes | 6 |
| $15^{\circ}$ | $60^{\circ}$ | yes | 12 |
For a nine - pointed star:
- Combination 1: $a = 10^{\circ},b = 60^{\circ}$
- Combination 2: $a = 15^{\circ},b = 70^{\circ}$
- Combination 3: $a = 20^{\circ},b = 80^{\circ}$