Question

as the pressure of a gas decreases to half its original value, what happens to the volume of the gas if temperature is held constant? (1 point)
the volume decreases to half of its original value
the volume decreases to one - fourth of its original value
the volume increases to twice its original value
the volume increases to four times its original value

Explanation:

Step1: Recall Boyle's law

$P_1V_1 = P_2V_2$ (constant - temperature)

Step2: Let $P_2=\frac{1}{2}P_1$

$P_1V_1=\frac{1}{2}P_1V_2$

Step3: Solve for $V_2$

Divide both sides by $\frac{1}{2}P_1$, we get $V_2 = 2V_1$

Answer:

The volume increases to twice its original value