Question

problem 2
a system of two equations has the solution (6, 2).
here is a graph of the one of the equations.
what could the other equation be?
a ( y = 4x - 2 )
b ( y = \frac{1}{2}x - 1 )
c ( y = \frac{2}{3}x - 1 )

Explanation:

Step1: Verify point (6,2) for option a

Substitute $x=6, y=2$ into $y=4x-2$:
$2 = 4(6) - 2 = 24 - 2 = 22$
$2
eq 22$, so invalid.

Step2: Verify point (6,2) for option b

Substitute $x=6, y=2$ into $y=\frac{1}{2}x-1$:
$2 = \frac{1}{2}(6) - 1 = 3 - 1 = 2$
$2 = 2$, so valid.

Step3: Verify point (6,2) for option c

Substitute $x=6, y=2$ into $y=\frac{2}{3}x-1$:
$2 = \frac{2}{3}(6) - 1 = 4 - 1 = 3$
$2
eq 3$, so invalid.

Answer:

b. $y = \frac{1}{2}x - 1$