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Question
problems 5 - 7: here is some information about the side lengths of two scaled copies, triangle a and triangle b.
- complete the table to determine the missing side lengths of each triangle.
- what is a constant of proportionality in this relationship?
Step1: Find the constant of proportionality
We know that when the side - length of triangle A is 1 and of triangle B is 3, the constant of proportionality $k$ is found by $\frac{\text{Side length of B}}{\text{Side length of A}}$. So $k = 3\div1=3$.
Step2: Find the missing side - length for $\text{Side length of A}=\frac{1}{2}$
Using the formula $\text{Side length of B}=k\times\text{Side length of A}$, substitute $k = 3$ and $\text{Side length of A}=\frac{1}{2}$. Then $\text{Side length of B}=3\times\frac{1}{2}=\frac{3}{2}$.
Step3: Find the missing side - length for $\text{Side length of B}=8$
Using the formula $\text{Side length of A}=\frac{\text{Side length of B}}{k}$, substitute $k = 3$ and $\text{Side length of B}=8$. Then $\text{Side length of A}=\frac{8}{3}$.
Step4: Find the missing side - length for $\text{Side length of A}=\frac{4}{3}$
Using the formula $\text{Side length of B}=k\times\text{Side length of A}$, substitute $k = 3$ and $\text{Side length of A}=\frac{4}{3}$. Then $\text{Side length of B}=3\times\frac{4}{3}=4$.
5.
| Side Length of Triangle A (in.) | Side Length of Triangle B (in.) |
|---|---|
| $\frac{1}{2}$ | $\frac{3}{2}$ |
| $\frac{8}{3}$ | 8 |
| $\frac{4}{3}$ | 4 |
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for question 6:
The constant of proportionality is 3.