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3 the product of a number and 1.5 is less than the absolute value of th…

Question

3 the product of a number and 1.5 is less than the absolute value of the difference between 20 and 5. what are all the possible values of the number? show your work.
solution
4 consider the inequalities $-\frac{1}{4}a > 3$ and $b - 12 > -3$. what values, if any, make both inequalities true? show your work.
solution
5 solve the inequality $x + 2\frac{1}{2} > -\frac{1}{2}$. graph the solution set on a number line. show your work.

Explanation:

Response
Problem 3

Step1: Define the number and absolute value

Let the number be \( x \). The absolute value of the difference between 20 and 5 is \( |20 - 5| \).
\( |20 - 5| = 15 \)

Step2: Set up the inequality

The product of the number and 1.5 is \( 1.5x \), and this is less than 15. So the inequality is \( 1.5x < 15 \).

Step3: Solve the inequality

Divide both sides by 1.5: \( x < \frac{15}{1.5} \)
\( x < 10 \)

Step1: Solve the first inequality \( -\frac{1}{4}a > 3 \)

Multiply both sides by -4. When multiplying or dividing an inequality by a negative number, the direction of the inequality sign changes.
\( a < 3\times(-4) \)
\( a < -12 \)

Step2: Solve the second inequality \( b - 12 > -3 \)

Add 12 to both sides: \( b > -3 + 12 \)
\( b > 9 \)

Step3: Analyze the solution sets

The solution for \( a \) is \( a < -12 \) and for \( b \) is \( b > 9 \). There is no overlap between the set of numbers less than -12 and the set of numbers greater than 9.

Step1: Subtract \( 2\frac{1}{2} \) from both sides

The inequality is \( x + 2\frac{1}{2} > -\frac{1}{2} \). Subtract \( 2\frac{1}{2} \) (which is \( \frac{5}{2} \)) from both sides:
\( x > -\frac{1}{2} - 2\frac{1}{2} \)

Step2: Simplify the right - hand side

\( -\frac{1}{2}-\frac{5}{2}=-\frac{6}{2}=-3 \)
So \( x > - 3 \)

Step3: Graph the solution on a number line

  • Draw a number line.
  • Place an open circle at -3 (since \( x > - 3 \), -3 is not included in the solution set).
  • Draw an arrow to the right of -3 to represent all numbers greater than -3.

Answer:

All possible values of the number are \( x < 10 \)

Problem 4