Question

pythagorean unit practice
possible points: 4.35
the length of a rectangular frame is 15 inches, and the width of the frame is 8 inches. what is the length of a diagonal of this frame in inches?
17 inches

Explanation:

Step1: Recall Pythagorean theorem

In a right - triangle (a rectangle's diagonal forms right - triangles with its length and width), the Pythagorean theorem is $a^{2}+b^{2}=c^{2}$, where $a$ and $b$ are the legs of the right - triangle and $c$ is the hypotenuse. Here, $a = 15$ (length) and $b = 8$ (width), and the diagonal is $c$.

Step2: Substitute values into the formula

$c^{2}=15^{2}+8^{2}=225 + 64=289$.

Step3: Solve for $c$

$c=\sqrt{289}=17$.

Answer:

17