Question

a quadratic equation of the form 0 = ax² + bx + c has a discriminant value of -16. how many real number solutions does the equation have?
-1
0
1
2

Explanation:

Step1: Recall discriminant rules

For a quadratic equation \(0 = ax^2 + bx + c\), the discriminant is \(D = b^2 - 4ac\). The number of real solutions is determined by:

• If \(D>0\), 2 real solutions.
• If \(D = 0\), 1 real solution.
• If \(D<0\), 0 real solutions (since square root of a negative number is not real).

Step2: Analyze given discriminant

Given \(D=-16\), which is less than 0.

Answer:

0 (corresponding to the option "0")