Question

question 10 of 10
for the function $f(t)=pe^{rt}$, if $p = 7$ and $r = 0.07$, then what is the value of $f(7)$ to the nearest tenth?
a. 940.0
b. 11.4
c. 9.4
d. 0.1

Explanation:

Step1: Substitute given values

Substitute $P=7$, $r=0.07$, $t=7$ into $f(t)=Pe^{rt}$:
$f(7)=7e^{(0.07\times7)}$

Step2: Calculate exponent term

Compute the exponent:
$0.07\times7=0.49$

Step3: Evaluate exponential value

Calculate $e^{0.49}\approx1.6323$

Step4: Compute final value

Multiply by 7:
$7\times1.6323\approx11.4$

Step5: Round to nearest tenth

The value is already to the nearest tenth.

Answer:

B. 11.4